(x-5)^2/3+100

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Solution for (x-5)^2/3+100 equation: 


x in (-oo:+oo)

((x-5)^2)/3+100 = 0

((x-5)^2)/3+(3*100)/3 = 0

(x-5)^2+3*100 = 0

x^2-10*x+325 = 0

x^2-10*x+325 = 0

x^2-10*x+325 = 0

DELTA = (-10)^2-(1*4*325)

DELTA = -1200

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

x belongs to the empty set

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